Biot-Savart Law and Its Applications

A current I flows around a closed path in the horizontal plane of the circle as shown in the figure. The path consists of eight arcs with alternating radii r and 2r. Each segment of arc subtends equal angle at the common centre P. The magnetic field produced by current path at point P is

A current of $i$ ampere is flowing through each of the bent wires as shown the magnitude and direction of magnetic field ${\rm O}$ is,

An infinitely long conductor $PQR$ is bent to form a right angle as shown. A current $I$ flows through $PQR$. The magnetic field due to this current at the point $M$ is ${\mathit{\text{H}}}_1$. Now, another infinitely long straight conductor $QS$ is connected at $Q$ so that the current in $PQ$ remaining unchanged. The magnetic field at $M$ is now ${\mathit{\text{H}}}_2$. The ratio $\frac{H_1}{H_2}$ is,

Find the magnetic induction at point O, if the current carrying wire is in the shape shown in the figure.

Two concentric coils, each of radius $2\mathrm{\pi } \mathrm{cm}$ and number of turns one are placed at right angle to each other. The currents flowing in coil are $3 \mathrm{A}$ and $4 \mathrm{A}$ respectively. Find the magnetic field induction at the centre of coils.

The magnetic field at the centre of a current carrying loop of radius $0.1 \mathrm{m}$ is $5\sqrt{5}$ times that at a point along its axis. The distance of this point from the centre of the loop is(in $\mathrm{cm}$)

State the similarities and dissimilitudes between the law governing the magnetic field by a current element and the law governing the electric field by a stationary charge

An element $△\mathrm{l}=△\mathrm{x}\hat{\mathrm{i}}$ is placed at the origin as shown in figure and carries a current $\mathrm{I}=2\mathrm{A}$ Find out the magnetic field at a point $\mathrm{P}$ on the y-axis at a distance of $1.0 \mathrm{m}$ due to the element $△\mathrm{x}=1 \mathrm{cm}$. Give also the direction of the field produced.

Derive the magnetic field due to a current element.

What is a current element?

The work done by a normal magnetic field in revolving a charge particle q in a circular path will be zero.

The work done by a normal magnetic field in revolving a charge particle q in a circular path will be _____.

How direction of magnetic field is identified? explain.

Calculate the magnetic field at the centre of a square loop which carries a current of $1.5 \mathrm{A}$, length of each side is $50 \mathrm{cm}$

What are the rules that are used to find the direction of the magnetic field?

A battery is connected between two points $A$ and $B$ on the circumference of a uniform conducting, ring of radius $r$ and resistance $R.$ One of the arcs $AB$ of the ring subtends an angle $\theta$ at the centre. The value of the magnetic induction at the centre due to the current ring is

A current $I$ flowing through the loop as shown in the adjoining figure. The magnetic field at centre O is

A current $I$ flowing through the loop as shown in the adjoining figure. The magnetic field at centre O is

$PQ$ and $RS$ are long parallel conductors separated by certain distance. $M$ is the mid-point between them (see the figure). The net magnetic field at $M$ is $B$. Now, the current $4 \mathrm{A}$ is switched off. The field at $M$ now becomes $B$.

The strength of magnetic field produced by current carrying circular wire_____if the number of turns of the wire increases.